Information for "Template:Calendar/doc"
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Display title | Template:Calendar/doc |
Default sort key | Calendar/doc |
Page length (in bytes) | 2,734 |
Namespace | Template |
Page ID | 34996 |
Page content language | en - English |
Page content model | wikitext |
Indexing by robots | Allowed |
Number of redirects to this page | 0 |
Number of subpages of this page | 0 (0 redirects; 0 non-redirects) |
Edit | Allow all users (infinite) |
Move | Allow all users (infinite) |
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Page creator | Decomposer (talk | contribs) |
Date of page creation | 08:55, April 30, 2019 |
Latest editor | Sunmarsh (talk | contribs) |
Date of latest edit | 16:28, January 11, 2021 |
Total number of edits | 2 |
Total number of distinct authors | 2 |
Recent number of edits (within past 90 days) | 0 |
Recent number of distinct authors | 0 |
Page transcluded on (1) | Template used on this page:
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Description | Content |
Article description: (description ) This attribute controls the content of the description and og:description elements. | The logic for the loop operation is as follows:
Calculate the difference between calendar value x and the start date value (numeral associated with the day of the week the month starts on), and add 1. If the result of this expression is less than one, then the calendar value is part of the previous month. For these calendar values, take the number of days in the previous month and add to them the result of the following expression: calendar value x - the start date value + 1. If the result of the expression in the first sentence is 1 or greater then determine if calendar value x is equal to or greater than the sum of the number of days in the current month and the start date value. If so, then the calendar value is part of the following month. For these calendar values, subtract the sum of the number of days in the current month and the start date value from calendar value x and add 1. For all other values (the calendar values associated with the days of the current month), calculate the difference between calendar value x and the start date value and add 1. |
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